Lecture III

Physics 367

How we use Energy


Energy

Recall Energy is the ability to do work:

W = Fx
where:
F = ma

As machines use energy there is an inevitable loss in the quality of the energy

This is caused by forces:

friction
drag
air resistance
etc.

When objects in contact move - work is done by these forces. This work is transferred to the system which then heats up.

All real mechanical systems produce less useful output work than the energy they take in.

Equivalent amounts of energy do not necessarily have the same capacity to do work.


Quality of Energy

Consider equal amounts of

electrical energy and
thermal energy.

Electricity can be used for any purpose.
Thermal energy can heat a room.

is difficult to use otherwise.

Thermal energy at very high temperature can be used to make electricity. But, only about 1/3 of the thermal energy ends up as electricity.


Real and Ideal Machines

Ideal machines: convert 100% of the energy input into output energy.

Energy in = Energy out.

Suppose that we do a certain amount of work that is the machine input. Then from our definition of work:

(work)in = (force)in x (distance)in

Similarly:

(work)out = (force)out x (distance)out

Ideal machines obey

(work)out = (work)in.

Example: The ideal lever:

work = F1d1 = F2d2


Real Machines do things other than useful work:

Levers bend
ropes stretch
friction acts on all machines.

The effect of all these: work is converted to

energy of compression
stretching [returned when we let go!]
thermal energy [which is lost].

Thus, real machines obey the relation:

(work)out < (work)in.


Example: a pulley with one end fixed may be used to lift a load.

The force exerted by the person doing the lifting is less than the load if movable pulleys are used because the rope at each side carries the same force T (see Figure). If the person pulls on the rope to lift the load with a constant velocity then F=ma T = 1/2W.


The pulley.


By pulling on one side of the rope to raise the weight the total distance traveled by the rope in the ideal case is twice the height through which the weight is raised.

In the ideal case, then, to raise the weight W, a height h,

the rope must be pulled a distance 2h.

Work done on the weight (the work out) =Wh.
Work done in pulling on rope (work in) = T(2h).

Since T = 1/2W

T(2h) =1/2 W(2h) = Wh.

The input work = the output work.


For the real rope

the force analysis still holds
the rope stretches.

So some of the input work must be stored in the stretched rope [or be used to battle friction].

The input work > Wh, the output work.

The transport of energy by a real machine involves a loss in available work.

This leads to the concept of efficiency


Power is the rate of doing work:

1kWh = 3.6x106 J
1kWh costs $0.10.


Example: Person Power. Walk up a flight of stairs 3m high in 20s.

mgh = 80kg x 9.8m/s2 x 3m = 2350 J
  (=180 lbs x 10 ft = 1800 ft-lbs)

P = 2350 J/20 s = 120 J/s = 120 W
  (=1800 ft-lbs/20 s = 90 ft-lbs/s)

1HP = 550 ft-lbs/sec
so a person does 1/5-1/10 HP!

get a horse to do the work!


The Engine

We consider the external and internal combustion engines, the turbine, and the rocket.


An external combustion engine.



An internal combustion engine.


The sequence of events in an internal combustion gasoline engine.


a) Intake stroke: gas and air mixture drawn in from carb.
b) Compression stroke.
c) Ignition: spark plug sparks, igniting the mixture.
d) Power stroke: piston pushed downward.
e) Exhaust stroke: burned gases [exhaust] released to the air.


Turbine engines.


The Steam Turbine.



The jet turbine.



The rocket engine.


Electrical Energy

Electrical energy comes mostly from burning coal or nuclear fuel.

Electricity Generation by Source, 1999 (AER 2000)

it is clean, convenient and safe
it is expensive



Electrical Forces

There is an electrical force (just like the gravitational force)

Fe = k q1 q2/ (distance of separation)2

=(9x109Nm2/C2) q1 q2/r2

Now since W = Fd the electric force does work by moving charges.


The unit of electric potential is the Volt (V) = (PE/charge) = (Work/charge)


Ohm’s Law:

The flow of electric charges creates a current . The unit of current is the Amp (A) = (charge/time):

1 Amp = 1 Coulomb/second

Various materials resist the flow of current (electrons) resistance . The unit of resistance is the Ohm. Ohms's law expresses the relationship between the electric potential (V), the current (I) and the resistance (R) of the line through which the current flows:

V=IR

Now

W = Fd = Vq

thus

P = W/t = V q/t = VI = IV


Transmission of electrical energy

If there is resistance in the line through which a current flows then V=IR is the voltage drop between the ends of the line. Then the power which is available at the end of the line is less than the power put in at the beginning of the line! The power lost is in the form of heat:

Ploss = I2R

To transmit electrical power efficiently

Ptrans = IVin
vs
Ploss = I2R

For a given P, choose Vin large to make I small
High tension wires (100-900kV)

How do we trade V for I.....transformers:

(VI)output = (VI)input

Conservation of energy.