Lecture III
Energy
Recall Energy is the ability to do
work:
As machines use energy there is an inevitable loss
in the quality of the energy
This is caused by forces:
friction
drag
air resistance
etc.
When objects in contact move - work is done by these forces. This work is transferred to the system which then heats up.
Consider equal amounts of
Electricity
can be used for any purpose.
Thermal energy
can heat a room.
Ideal machines: convert 100% of the energy input into output energy.
Energy in = Energy out.
Suppose that we do a certain amount of work that is the machine input. Then from our definition of work:
(work)in = (force)in x (distance)in
Similarly:(work)out = (force)out x (distance)out
Ideal machines obey
(work)out = (work)in.
Example: The ideal lever:
work = F1d1 = F2d2
The effect of all these: work is converted to
Thus, real machines obey the relation:
(work)out < (work)in.
Example: a pulley with one end fixed may be used to lift a load.
The force exerted by the person doing the lifting is less than the load
if movable pulleys are used because the rope at each side carries the same
force T (see Figure). If the person pulls on the rope to lift the load
with a constant velocity then F=ma
T = 1/2W.
The pulley.
By pulling on one side of the rope to raise the weight the total distance traveled by the rope in the ideal case is twice the height through which the weight is raised.
In the ideal case, then, to raise the weight W, a height h,
the rope must be pulled a distance 2h. Work done on the weight (the work out) =Wh.
Work done in pulling on rope (work in) = T(2h).Since T = 1/2W
T(2h) =1/2 W(2h) = Wh.
The input work = the output work.
the force analysis still holds
the rope stretches.
So some of the input work must be stored in the stretched rope [or be used to battle friction].
The input work > Wh, the output work.
The transport of energy by a real
machine involves a loss in available work.
This leads to the concept of efficiency
Power is the rate of doing work:
Example: Person Power. Walk up a flight of stairs 3m high in 20s.
mgh = 80kg x 9.8m/s2 x 3m = 2350 J
(=180 lbs x 10 ft = 1800 ft-lbs) P = 2350 J/20 s = 120 J/s = 120 W
(=1800 ft-lbs/20 s = 90 ft-lbs/s)1HP = 550 ft-lbs/sec so a person does 1/5-1/10 HP! get a horse to do the work!
The Engine
We consider the external and internal combustion engines, the turbine, and the rocket.
The sequence of events in an internal combustion gasoline engine.
Turbine engines.
Electrical energy comes mostly from burning coal or nuclear fuel.
There is an electrical force (just like the gravitational force)
Fe = k q1 q2/ (distance of separation)2
=(9x109Nm2/C2)
q1 q2/r2
Now since W = Fd the electric force does work by moving
charges.
Ohms Law:
The flow of electric charges creates a current . The unit of current is the Amp (A) = (charge/time):
Various materials resist the flow of current (electrons)
resistance
. The unit of resistance is the Ohm. Ohms's law expresses the
relationship between the electric potential (V), the current (I) and the
resistance (R) of the line through which the current flows:
Now
W = Fd = Vq
thus
P = W/t = V q/t = VI = IV
Transmission of electrical energy
If there is resistance in the line through which a current flows then V=IR is the voltage drop between the ends of the line. Then the power which is available at the end of the line is less than the power put in at the beginning of the line! The power lost is in the form of heat:
Ploss = I2R
To transmit electrical power efficiently
Ptrans = IVin
vs
Ploss = I2R
How do we trade V for I.....transformers:
(VI)output = (VI)input
Conservation of energy.