*Write your name and answers on this sheet and hand it in at the
end.*

**After the indicated time, move on to the next activity,
even if you are not finished!**

Start up MBoltz and EBoltz from the H133 webpage.

- Do T7B.4. What should you choose for x1?
For x2, does it matter if you choose 100 or 200? Why not?
Argue that your result for the probability is reasonable.

- As a warm-up problem for using EBoltz, do T7B.6.

- Now for a more interesting exploration. The default energies for
EBoltz are E = epsilon*n, as for the Einstein solid. What is the
approximate average energy in the high-temperature limit? (Give
it as a multiple of kT.)

Now change the energy to be E = epsilon*n^{2}[you get n^{2}by typing n^2]. What is the approximate average energy in the high-temperature limit?

Now try E = epsilon * sqrt(n) [this is how you write a square root]. Once again, what is the approximate average energy in the high-temperature limit? [NOTE: Don't try kT/epsilon much greater than 10, or it will take forever.]

Have you discovered a pattern? What is it? Predict first and then test with E = epsilon*n^{3}.

- Start with some basic applications of equations (T8.7) and (T8.8).
Do T8T.1 and T8T.2, explaining your answers.

- Do T8T.5. What kind of process is this? Show your work.

- Do T8B.8. [Hint: Phase changes are discussed in Section T8.4.]

- The concept of a "suitable replacement process" (section T8.6)
is important
but sometimes tricky. You need to have the same initial and final
macrostates and the process must be quasistatic. Use T8T.8 and T8T.9
to test your understanding. Only one answer each in T8T.8
and T8T.9 works;
why do the others fail? In T8T.9,
note that the ideal gas law applies to both
the initial and final gases; your replacement process must be consistent.

A perfect engine, which converts thermal energy (heat)
*completely* into work, would violate the 2nd Law of
Thermodynamics. Flowing heat carries entropy from one object
to another, but flowing work does not. (E.g., raising a weight
or adiabatically compressing a gas doesn't change the entropy.)
A real heat engine needs to expel the entropy the engine
gets from the heat source (a hot reservoir at T_{H}),
so there needs to be a cold reservoir at T_{C}.

According to the first law, |W| = |Q_{H}| - |Q_{C}|,
where Q_{H} is the heat energy from the hot reservoir and
Q_{C} is the heat energy sent to the cold reservoir.
Then the efficiency e is given by

e = benefit/cost = |W|/|Q_{H}| = 1 - |Q_{C}|/|Q_{H}|
< (T_{H}-T_{C})/T_{H}
(the < is really "less than or equal to").

- To get warmed up at applying the idea of efficiency, do T9T.3,
being careful to identify |W|, |Q
_{H}|, and |Q_{C}| and then do T9T.5. Do you think the personal fan is practical?

- Is there a symmetry between heat energy and work? Answer T9B.1.

- Try an engineering application: the power plant proposed in
T9S.8, making use of the basic efficiency relation above.
Be careful with the temperatures given in centrigrade!

- Let's finish with some T9S questions that we'll discuss on
Thursday. Give a one or two sentence
answer to each of the following:
- T9S.2.

- T9S.3.

- T9S.4.

- T9S.2.

furnstahl.1@osu.edu